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7 March, 09:53

Estimate the molar mass of a gas that effuses at 1.80 times the effusion rate of carbon dioxide. answer in units of g/mol.

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  1. 7 March, 10:17
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    From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.

    Therefore; R1/R2 = √mm2/√mm1

    The molecular mass of Carbon dioxide is 44 g

    Hence; 1.8 = √ (44/x

    3.24 = 44/x

    x = 44/3.24

    = 13.58

    Therefore, the molar mass of the other gas is 13.58 g/mol
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