24 January, 21:52
How many grams of sodium iodide, nai, must be used to produce 97.1 g of iodine, i2?
24 January, 23:11
Iodine is prepared both in the laboratory and commercially by adding Cl2 (g) to an aqueous solution containing sodium iodide: 2NaI (aq) + Cl2 (g) - - - > I2 (s) + 2NaCl (aq) (97.1 g I2) / (253.8089 g I2/mol) x (2 mol NaI / 1 mol I2) x (149.8942 g NaI/mol) = 12.7 g NaI.
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