What is the mass, in grams, of solute in 255mL of a 0.0525M solution of KMnO4 (MM =

158.04g/mol) ?

Mass = 2.12 g

Explanation:

Given dа ta:

Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)

Molarity = 0.0525 M

Mass in gram = ?

Solution:

First of all we will calculate the number of moles.

Molarity = number of moles of solute / volume in litter

0.0525 M = number of moles of solute / 0.255 L

Number of moles of solute = 0.0525 M * 0.255 L

Number of moles of solute = 0.0134 mol

Mass in gram:

Number of moles = mass / molar mass

Mass = moles * molar mass

Mass = 0.0134 mol * 158.04 g/mol

Mass = 2.12 g