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27 December, 05:28

1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011)

weigh?

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Answers (1)
  1. 27 December, 05:43
    0
    Mass = 4.6 g

    Explanation:

    Given dа ta:

    Number of molecules of sucrose = 8.1 * 10²¹ molecules

    Mass of sucrose = ?

    Solution:

    First of all we will calculate the number of moles by using Avogadro number.

    1 mole * 8.1 * 10²¹ molecules / 6.022*10²³ molecules

    1.35 * 10⁻² mol

    Mass of sucrose:

    Mass = number of moles * molar mass

    Molar mass = 342.3 g/mol

    Mass = 1.35 * 10⁻² mol * 342.3 g/mol

    Mass = 462.1 * 10⁻² g

    Mass = 4.6 g
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