How many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? hints how many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? 5.47 g 5.59 g 89.5 g 2.52 x 10-4 g?

Question

Elisabeth Gregory

Chemistry

22 February, 11:13

How many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? hints how many grams of (nh4) 3po4 are needed to make 0.250 l of 0.150 m (nh4) 3po4? 5.47 g 5.59 g 89.5 g 2.52 x 10-4 g?

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Santino Hurst · Answer 1

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate the mass of the solute by first determining the number of moles needed. And by using the molar mass, we can convert it to units of mass.

Moles (nh4) 3po4 = 0.250 L (0.150 M) = 0.0375 moles (nh4) 3po4

Mass = 0.0375 mol (nh4) 3po4 (149.0867 g / mol) = 5.59 g (nh4) 3po4