A gas at STP occupies 22.4 L if the temperature is changed to 260 K and the pressures changed it to 0.50 ATM what will the new volume be

The new volume will be 42, 7 L.

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. The conditions STP are: 1 atm of pressure and 273 K of temperature.

P1xV1/T1 = P2xV2/T2

1 atmx 22,4 L/273K = 0,5atmx V2/260K

V2 = ((1 atmx 22,4 L/273K) x 260K) / 0,5 atm = 42, 67L