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26 July, 06:19

Calculate the mass of nitrogen dioxide present in a 0.527 L container if the pressure is 225.5 kPa and the temperature is 20.1°C.

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  1. 26 July, 06:48
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    Answer;

    = 2.2448 g

    Explanation;

    Using the equation;

    PV = nRT, where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol-1.

    Pressure = 225.5 kPa. or 2.226 atm

    Temperature = 20.1 + 273 = 293.1 Kelvin

    Volume = 0.527 L

    Therefore; to get the mass of NO2 we first get the number of moles

    n = PV/RT

    = (2.226 * 0.527) / (0.08206 * 293.1)

    = 0.0488 Moles

    But; 1 mole of NO2 = 46 g/mol

    Thus; the mass of NO2

    = 0.0488 moles * 46 g/mol

    = 2.2448 g
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