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26 September, 18:15

How many calcium ions are in a sample of 7.36 grams of calcium phosphate?

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  1. 26 September, 18:18
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    5.72 x 10^22. There are 5.72 x 10^22 Ca^ (2+) ions in 7.36 g Ca3 (PO4) 2.

    a) Moles of Ca3 (PO4) 2

    MM of Ca3 (PO4) 2 = [3x40.08 + 2 (30.97 + 4x16.00) ] g/mol

    = (120.24 + 2x94.97) g/mol = (120.24 + 189.94) g/mol = 310.18 g/mol

    Moles of Ca3 (PO4) 2

    = 7.36 g Ca3 (PO4) 2 x [1 mol Ca3 (PO4) 2]/[310.18 g Ca3 (PO4) 2]

    = 0.023 73 mol Ca3 (PO4) 2

    b) Formula units (FU) of Ca3 (PO4) 2

    Formula units of Ca3 (PO4) 2

    = 0.023 73 mol Ca3 (PO4) 2 x [6.022 x 10^23 FU Ca3 (PO4) 2]/[1 mol Ca3 (PO4) 2] = 1.429 x 10^22 FU Ca3 (PO4) 2

    c) Ions of Ca

    No. of Ca ions

    = 1.429 x 10^22 FU Ca3 (PO4) 2 x [4 Ca^ (2+) ions]/[1 FU Ca3 (PO4) 2]

    = 5.72 x 10^22 Ca^ (2+) ions
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