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26 August, 12:46

How many grams do 6.7*1023 atoms of argon weigh?

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  1. 26 August, 13:03
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    44.4g

    Explanation:

    First we must find the moles of argon.

    To do this, divide the number of atoms by Avogadro's number (6.022 * 10^23)

    n = (6.7 * 10^23) / (6.022 * 10^23)

    n=1.11258718034

    Now to find mass, we complete the calculation

    m = n * MM

    where

    m is mass

    n is moles

    MM is molecular mass

    m = 1.11258718034 * 39.948

    m = 44.4456326802

    m = 44.4g
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