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30 July, 03:15

Dinitrogen monoxide gas decomposes to form nitrogen gas and oxygen gas. How many grams of oxygen are formed when 10.0 g of dinitrogen monoxide decomposes?

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  1. 30 July, 03:37
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    There is formed 3.6352 grams of oxygen

    Explanation:

    Step 1: The balanced equation

    2N2O (g) ⇔2N2 (g) + O2 (g)

    Step 2: Calculate moles of dinitrogen monoxide

    Moles = mass / Molar mass

    Moles of N2O = 10 grams of N2O / 44.01 g/mole

    Moles of N2O = 0.227 moles

    Step 3: Calculate moles of oxygen

    When 2 moles of N2O is consumed, there is produced 1 mole of O2 (and 2 moles of N2)

    That means for 0.2272 moles of N2O consumed, there is produced 0.1136 moles of O2

    Step 4: Calculate mass of O2

    mass of O2 = moles of O2 * Molar mass of O2

    mass of O2 = 0.1136 moles * 32 g/moles

    mass of O2 = 3.6352 grams

    There is formed 3.6352 grams of oxygen
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