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9 October, 09:04

A solution of a sugar with the chemical formula (c12h22o11) is prepared by dissolving 8.45 g in 250.0 ml of water at 25

c. the density of this solution is 1.21 g/cm3. calculate the concentration in terms of molarity, molality, weight percent and ppm. assume that the volume of the solution is equal to the volume of the solvent. show your work.

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  1. 9 October, 09:17
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    A. Concentration in terms of molarity

    First, calculate for the molar mass of the given solution, C12H22O11.

    m = 12 (12) + 22 (1) + 11 (16) = 232

    Calculate for the number of moles.

    n = 8.45 g / 232 g/mol = 0.036422 moles

    Divide the determined number of moles by volume of solution in L.

    V (solution) = (250 mL) (1 L/1000 mL) = 0.25 L

    The concentration in molarity is determined by dividing the number of moles by the volume of solution in liters.

    M = 0.03622 moles / 0.25 L = 0.146 moles/L

    b. Concentration in terms of molality

    Calculate the mass of the solvent in kilogram given the volume and its density.

    m (solvent) = (1.21 g/cm3) (250 mL) (1 kg/1000 g) = 0.3025 kg

    Divide the calculated number of moles by the mass of the solvent in kilograms.

    molality = 0.036422 moles/0.3025 kg = 0.12 molal

    c. Concentration in terms of weight percent.

    The total weight of the solution is equal to 302.5 g.

    weight percent of solute = (8.45 g / 302.5 g) (100%) = 2.79%

    d. Weight percent in ppm.

    weight percent of solute x (10000 ppm/1%)

    = (2.79%) (10000 ppm/1%) = 27933.88 ppm
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