A sample of oxygen has a volume of 128 milliliter at a pressure of 500.0 mmhg calculate the volume this sample would occupy at standard pessure

84.2mL

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 128mL

Initial pressure (P1) = 500mmHg

Final pressure (P2) = stp = 760mmHg

Final volume (V2) = ... ?

Thus, the new volume of the gas can be obtained by using the Boyle's law equation as follow:

P1V1 = P2V2

500 x 128 = 760 x V2

Divide both side by 760

V2 = (500 x 128) / 760

V2 = 84.2mL

Therefore, the new volume of the gas is 84.2mL