Ask Question
5 May, 05:35

Calculate the rate of heat conduction out of the human body, assuming that the core internal temperature is 37.0°C, the skin temperature is 34.8°C, the thickness of the tissues between averages 1.00 cm, and the surface area is 1.75 m2. The conductivity of tissue is 0.20 J / (s · m · °C).

+1
Answers (1)
  1. 5 May, 05:48
    0
    The answer is 105 W

    Explanation:

    Solution

    Given that:

    The core temperature is = 37.0°C

    The skin temperature is = 34.8°C,

    The thickness of the tissues is on the average of = 1.00 cm

    The surface area = 1.75 m²

    The conductivity of tissue is = 0.20 J (s. m. °C)

    Now,

    The rate of heat transfer through a means of conduction of materials is represented as follows:

    Q / t = kA (T₂ - T₁) / d

    Where

    k = the thermal conductivity

    A = denoted as the surface area

    d = the thickness

    (T₂ - T₁) = is the temperature difference of the body

    Thus

    Q/t = kA (T₂ - T₁) / d

    We now substitute the values of 1.75 m² for A, 0.20 J / (s. m. °C) for k, 37.0°C, for T₁, 34.8°C for T₂, 1.00 cm for d

    We have the following inputs:

    Q/t = (0.20 J/s. m. °C) (1.75 m²) (37.0°C - 34.8°C) / ((1 cm) (10^⁻2/1 cm))

    Now

    Q/t = (0.20 J/s. m. °C) (1.75 m²) (3.00 ° C) / (0.01 m)

    Q/t = 1.05 / (0.01)

    Q/t = 105 J/s

    Therefore, the rate of heat conduction is 105 W
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calculate the rate of heat conduction out of the human body, assuming that the core internal temperature is 37.0°C, the skin temperature is ...” in 📗 Engineering if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers