If p =.8 and n = 50, then we can conclude that the sampling distribution of pˆ p ^ is approximately a normal distribution.

It is true that the sampling distribution of the proportions is approximately a normal distribution.

Explanation:

Solution

Given that:

N = 50

P = 0.8

Thus

p ^ = √p (1-p) / n

p ^=√0.8 (1-0.8) / 50

p ^ = 0.0566

Therefore, we conclude that the sampling distribution of the proportions is approximately a normal distribution.