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12 June, 16:23

A triangle has vertices P (2,-1,0), Q (4,1,1), R (4,-5,4). Determine if the triangle is a right triangle (a) Using the Pythagorean theorem; (b) Using the properties of the dot product.

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  1. 12 June, 16:50
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    see answers below

    Step-by-step explanation:

    a) using the Pythagorean theorem

    PQ = (2,-1,0) - (4,1,1) = (-2,-2,-1)

    QR = (4,1,1) - (4,-5,4) = (0,6,-3)

    RP = (4,-5,4) - (2,-1,0) = (2,-4,4)

    then

    length 1 = |PQ| = √[ (-2) ² + (-2) ² + (-1) ²] = √9 = 3

    length 2 = |QR| = √[ (0) ² + (6) ² + (-3) ²] = √45

    length 3 = |RP| = √[ (2) ² + (-4) ² + (-4) ²] = √36 = 6

    then if the triangle is a right triangle

    length 2 = √[ (length 1) ² + (length 3) ²] = √ (3²+6²) = √45

    then our assumption is correct

    b) using the properties of dot product

    PQ * RP = (-2,-2,-1) * (2,-4,4) = 2 * (-2) + (-2) * (-4) + (-1) * 4 = - 4 + 8 - 4 = 0

    thus PQ is perpendicular to RP. Then the triangle PQR is a right one
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