In a certain college class, 40% of the admitted students were in top 10% of their high school class, 25% were in the next 10%, and the remaining 35% were below the top 20%. Of these students, 90%, 70%, and 20% were passing this course, respectively. If a randomly selected student is failing, then what is the probability that this student was below 20% of his or her high school class (round off to second decimal place) ?

Question

Zachariah Chan

Mathematics

8 June, 18:03

In a certain college class, 40% of the admitted students were in top 10% of their high school class, 25% were in the next 10%, and the remaining 35% were below the top 20%. Of these students, 90%, 70%, and 20% were passing this course, respectively. If a randomly selected student is failing, then what is the probability that this student was below 20% of his or her high school class (round off to second decimal place) ?

+1

Answers (1)

Know the Answer?

Braedon Bradley · Answer 1

0.71

Step-by-step explanation:

The fraction of students failing is the sum of the fractions of students failing in each category. Those fractions are ...

top 10%: 0.40 * (1 - 0.90) = 0.04

next 10%: 0.25 * (1 - 0.70) =.075

bottom 80%: 0.35 * (1 - 0.20) = 0.28

So, the total fraction of students failing is ...

0.04 + 0.075 + 0.28 = 0.395

The desired probability is ...

p (bottom 80% | failing) = p (bottom 80% & failing) / p (failing)

= 0.28/0.395 ≈ 0.7089 ≈ 0.71