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20 January, 13:07

What equation can be solved to find the time when the pumpkin is 10 feet from the ground

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  1. 20 January, 13:26
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    H (t) = h0+vt - (at^2) / 2 we can assume that this problem is near to the earth's surface so a≈32ft/s^2

    h (t) = h0+vt-16t^2 now you need to plug in the initial velocity where v is and the initial height where h0 is ...
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