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18 April, 18:56

2. The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.

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  1. 18 April, 19:32
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    74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74 = x + 26+2x. Now solve.

    74=3x+26

    48=3x

    16=x

    So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.

    y=26+2x

    y=26+2 (16)

    y=26+32

    y=58.

    So to check our answer we can plug in both values into the beginning equation.

    74=58+16

    74=74.

    So to sum this up the smaller number is 16 and the larger number is 58.
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