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1 March, 06:47

a private jet can fly 1,210 miles against the headwind in the same amount of time it can fly 1,694 miles with a 25 mph tailwind. find the speed of the jet

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  1. 1 March, 07:13
    0
    Let us assume speed of the Jet = x mph.

    We are given speed of wind = 25 mph.

    Total speed of the Jet with tailwind = (x+25) mph.

    Total speed of the Jet with headwind = (x-25) mph.

    We know, relation among time, rate and time is given by formula:

    Time = Distance/Speed.

    Time taken against the headwind = 1210 / (x-25). Time taken against the tailwind = 1694 / (x+25).

    Both times are same.

    Therefore,

    1210 / (x-25) = 1694 / (x+25)

    On cross multiplying, we get

    1210 (x+25) = 1694 (x-25)

    1210x + 30250 = 1694x - 42350.

    Adding 42350 on both sides,

    1210x + 30250+42350 = 1694x - 42350 + 42350.

    1210x + 72600 = 1694x

    Subtracting 1210x from both sides, we get

    1210x-1210x + 72600 = 1694x - 1210x

    72600 = 484x.

    Dividing both sides by 484, we get

    72600/484 = 484x/484.

    150 = x. Therefore, the speed of the Jet is 150 mph ...
  2. 1 March, 07:15
    0
    Step-by-step explanation:

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