The sum od the squares of two consecutive even integers is 164. Find the integers.

Let x be the smaller integer, then x+2 is the larger integer.

We're given

x^2 + (x+2) ^2=164

Expand and simplify

2x^2+4x+4=164

x^2+2x-80=0

(x-8) (x+10) = 0

=> x=-10 or x=8.

Therefore the integers are{8,10} or {-10,-8}.

Note: question asks for integers, so negative integers count.