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Yareli Joyce
Mathematics
4 February, 15:27
Solve 8y-3 (4-2y) = 6 (y+1)
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Judith
4 February, 15:34
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Y=9/4 that's a fraction
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Samir Berry
4 February, 15:51
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8y - 3 (4 - 2y) = 6 (y + 1)
Step 1: Simplify both sides of the equation.
8y - 3 (4 - 2y) = 6 (y + 1)
8y + (-3) (4) + (-3) ( - 2y) = (6) (y) + (6) (1) (Distribute)
8y + - 12 + 6y = 6y + 6 (8y + 6y) + (-12) = 6y + 6 (Combine Like Terms)
14y + - 12 = 6y + 6
14y - 12 = 6y + 6
Step 2: Subtract 6y from both sides.
14y - 12 - 6y = 6y + 6 - 6y
8y - 12 = 6
Step 3: Add 12 to both sides.
8y - 12 + 12 = 6 + 12
8y = 18
Step 4: Divide both sides by 8. 8y / 8 = 18/8
y = 9/4
Answer: y = 9 / 4
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