Use the inequality to answer Parts 1-3.

-3 (x - 2) ≤

Part 1: Solve the inequality. Leave answer in terms of a whole number or reduced improper fraction.

Part 2: Write a verbal statement describing the solution to the inequality.

Part 3: Verify your solution to the inequality using two elements of the solution set.

Use a word processing program or handwrite your responses to Parts 1-3. Turn in all three responses.

And theres another one.

Solve the inequality and complete a line graph representing the solution. In a minimum of two sentences, describe the solution and the line graph.

8 ≥ 3x + 5

This is the last one ...

Solve the inequality. Using a verbal statement, in simplest terms, describe the solution of the inequality. Be sure to include the terms, "greater than", "greater than or equal to", "less than", or "less than or equal to".

-2x + 3 > 3 (2x - 1)

Will give brainl (y) (iest).

Question

Luna Orr

Mathematics

26 July, 14:45

Use the inequality to answer Parts 1-3.

-3 (x - 2) ≤

Part 1: Solve the inequality. Leave answer in terms of a whole number or reduced improper fraction.

Part 2: Write a verbal statement describing the solution to the inequality.

Part 3: Verify your solution to the inequality using two elements of the solution set.

Use a word processing program or handwrite your responses to Parts 1-3. Turn in all three responses.

And theres another one.

Solve the inequality and complete a line graph representing the solution. In a minimum of two sentences, describe the solution and the line graph.

8 ≥ 3x + 5

This is the last one ...

Solve the inequality. Using a verbal statement, in simplest terms, describe the solution of the inequality. Be sure to include the terms, "greater than", "greater than or equal to", "less than", or "less than or equal to".

-2x + 3 > 3 (2x - 1)

Will give brainl (y) (iest).

+3

Answers (1)

Know the Answer?

Olive Estrada · Answer 1

1. Incomplete

2. 8≥ 3 x + 5

⇒8-5≥3 x

⇒ 3 ≥ 3 x

Dividing both sides by 3

1≤ x or x ≥ 1 is the solution of above inequality. i. e x∈[1,0).

The solution of the above inequality is that x lies in the interval from 0 to 1 represented as 0≤x<1.

3. - 2 x + 3 > 3 (2 x - 1)

⇒ - 2 x + 3> 3 * 2 x - 3 * 1 ⇒ [using distributive property which is a (b+c) = a*b + a * c]

⇒-2 x - 6 x > - 3-3 →[ Bringing like terms together]

⇒ - 8 x > - 6

Cancelling negative sign from both sides

if,-a>-b, then a
⇒8 x< 6

⇒x<6/8

⇒x<3/4

x∈ (-∞,3/4)

The solution of the above inequality is x should be less than three by four.