Find the 29th term of the following sequence. 13.1,3.1,-6.9,-16.9

Consider this option:

1. this arithmetic sequence consists of b1; b2; b3; b4; ...; bₐ, where b1=13.1; b2=3.1; b3=-6.9; b4=-16.9, etc. and the difference (d) between bₐ₊₁ and bₐ is (-10).

2. using formula for bₐ of arithmetic sequence: bₐ=b₁+d (a-1), where a - number of term of this sequence, it is possible to find b₂₉: b₂₉=b₁+d (29-1) = 13.1-10*28=-266.9.

answer: - 266.9