Ask Question
22 July, 22:55

Which functions domain consists of all real numbers except - 2?

a) f (x) = 1/x+2

b) f (x) = 2x

c) f (x) = 2x-2

d) f (x) = 1/vx+2

0
Answers (1)
  1. 22 July, 23:31
    0
    option (a) f (x) = 1/x+2

    Step-by-step explanation:

    (a) f (x) = 1 / x+2

    To find the restriction for domain, we set the denominator = 0 and solve for x

    x+2 = 0, so x=-2

    When x=-2 then denominator becomes 0 that is undefined.

    So, domain is all real numbers except - 2

    (b) f (x) = 2x

    In this function, there is no denominator or square root or log function

    so there is no restriction for x, hence domain is all real numbers

    (c) f (x) = 2x-2

    In this function, there is no denominator or square root or log function

    so there is no restriction for x, hence domain is all real numbers

    f (x) = 1 / sqrt (x+2)

    if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined

    x+2>0, x>-2

    Hence domain is all real numbers that are greater than - 2
Know the Answer?