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3 September, 13:22

What is the equation for a line that goes through (0,-1) and (3,1)

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  1. 3 September, 13:24
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    y=2/3x-1

    Step-by-step explanation:

    m = (y2-y1) / (x2-x1)

    m = (1 - (-1)) / (3-0)

    m = (1+1) / 3

    m=2/3

    y-y1=m (x-x1)

    y - (-1) = 2/3 (x-0)

    y+1=2/3 (x)

    y+1=2/3x

    y=2/3x-1
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