A cooler contains 11 cans of soda; 5 colas, 5 orange, and 1 cherry. Two cans are selected at random without replacement. Find the probability that at least one can is cola.

Question

Gus

Mathematics

3 January, 22:13

A cooler contains 11 cans of soda; 5 colas, 5 orange, and 1 cherry. Two cans are selected at random without replacement. Find the probability that at least one can is cola.

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Answers (2)

Know the Answer?

Conner Walsh · Answer 1

There is a 20.2 percent chance he will get at least one cola

Kallie Lowe · Answer 2

Chance that the first can chosen is cherry is 1/11.

Chance that the first can chosen is not cherry and the second can chosen is cherry is (10/11) (1/10) = 1/11.

So the required probability is 1/11 + 1/11 = 2/11.