Find the solution (s) to the system of equations. y = x^2 - 2x - 3 y = x - 3

two solutions : (0,-3), (3,0)

Step-by-step explanation:

hello:

y = x² - 2x - 3 ... (*)

y = x - 3 ... (**)

x²-2x-3 = x - 3

x²-3x=0

x (x-3) = 0

x=0 or x-3=0

x=0 or x=3

but : y=x-3

1) x=0 y=0-3=-3

2) x=3 y=3-3=0

two solutions : (0,-3), (3,0)