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23 March, 20:41

Find the solution (s) to the system of equations. y = x^2 - 2x - 3 y = x - 3

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  1. 23 March, 20:57
    0
    two solutions : (0,-3), (3,0)

    Step-by-step explanation:

    hello:

    y = x² - 2x - 3 ... (*)

    y = x - 3 ... (**)

    x²-2x-3 = x - 3

    x²-3x=0

    x (x-3) = 0

    x=0 or x-3=0

    x=0 or x=3

    but : y=x-3

    1) x=0 y=0-3=-3

    2) x=3 y=3-3=0

    two solutions : (0,-3), (3,0)
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