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12 October, 19:25

Which expression is equivalent to g^-m : g^n

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  1. 12 October, 19:51
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    G^-m : g^n

    1st g^-m=1/g^m, hence g^-m : g^n = (1/g^m) / (g^n) = = > 1 / (g^m) (g^ (n)

    ==> 1 / (g^m+n) or g^ (-m-n)
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