A test charge is introduced into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What would the force on the test charge be where the electric field is 8E?

Somebody explain how you would get the answer.

Question

Snuffles

Physics

13 February, 18:57

A test charge is introduced into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What would the force on the test charge be where the electric field is 8E?

Somebody explain how you would get the answer.

+3

Answers (1)

Know the Answer?

Kayleigh Combs · Answer 1

We know, q = F / E

q = 2 / 4

q = 1/2

Now, we have: q = 1/2 and E = 1

Substitute the value into the expression:

F = E. q

F = 1/2 * 1 = 1/2

In short, Your Answer would be 1/2

A test charge is introduced into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What would the force on the test charge be where the electric field is 8E?Somebody explain how you would get the answer.

A test charge is introduced into the electric field of a charge. It feels a force of 2F where the electric field is 2E. What would the force on the test charge be where the electric field is 8E?

Somebody explain how you would get the answer.