A person lifts a 4.7 kg cement block a vertical distance of 1.1 m and then carries the block horizontally a distance of 5.7 m. The acceleration of gravity is 9.81 m/s 2. a) Determine the work done by the person in the process. Answer in units of J

The work done by the person in the process = 313.53 J

Explanation:

Work: This is defined as the product of force and distance. The unit of work is Joules (J). Because energy and work have the same unit, they can be used interchangeably during calculations in science.

Work done in the process = Work done i lifting the cement through the vertical distance + work done in carrying the cement along the horizontal distance.

Therefore, Wp = Wv + Wh ... equation 1

Where Wp = work dine in the process, Wv = vertical work done. Wh = horizontal work done.

Wv = mgHv ... Equation 2

Wh = mgHh ... Equation 3

Where m = mass of the cement, g = acceleration due to gravity, Hv = vertical distance, Hh = horizontal distance.

Substituting Equation 2 and 3 into Equation 1

Wp = mgHv + mgHh ... Equation 4

Given: m = 4.7 kg, Hv = 1.1 m, Hh = 5.7 m g = 9.8 1m/s²

Substituting these values into equation 4

Wp = (4.7*9.81*1.1) + (4.7*9.81*5.7)

Wp = 50.7177 + 262.8099

Wp = 313.53 J.

Therefore, The work done by the person in the process = 313.53 J