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2 October, 20:52

Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 100 kg ball traveling at 5 m/s. A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 kg person falling at 5 m/s would have kinetic energy.

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  1. 2 October, 21:02
    0
    A 1,000 kg ball traveling at 5 m/s would have 10 times more kinetic energy.

    A 10 kg ball traveling at 5 m/s would have 10 times less kinetic energy.

    A 100 kg person falling at 5 m/s would have the same kinetic energy.

    Explanation:

    Edg 2020
  2. 2 October, 21:20
    0
    Okay, first off, the formula for Kinetic Energy is:

    KE = 1/2 (m) (v) ^2

    m = mass

    v = velcoity (m/s)

    Using this formula, we can then calculate the kinetic energy in each scenario:

    1) KE = 1/2 (100) (5) ^2 = 1,250 J

    2) KE = 1/2 (1000) (5) ^2 = 12,500 J

    3) KE = 1/2 (10) (5) ^2 = 125 J

    4) KE = 1/2 (100) (5) ^2 = 1,250 J
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