PART ONE

In a 31 s interval, 320 hailstones strike a glass

window of area 1.455 m^2

at an angle 70◦ to the window surface. Each hailstone has a mass of

6 g and speed of 4.6 m/s. If the collisions are elastic, find the average

force on the window.

Answer in units of N.

PART TWO

Find the pressure on the window.

Answer in units of N/m^2

PART TWO

Question

Zachariah Noble

Physics

15 July, 23:44

PART ONE

In a 31 s interval, 320 hailstones strike a glass

window of area 1.455 m^2

at an angle 70◦ to the window surface. Each hailstone has a mass of

6 g and speed of 4.6 m/s. If the collisions are elastic, find the average

force on the window.

Answer in units of N.

PART TWO

Find the pressure on the window.

Answer in units of N/m^2

PART TWO

+1

Answers (1)

Know the Answer?

Gaven Hopkins · Answer 1

Impulse = change in momentum

F Δt = m Δv

F (31 s) = (320 * 0.006 kg) (4.6 sin 70° m/s - (-4.6 sin 70° m/s))

F = 0.535 N

Pressure = force / area

P = F / A

P = 0.535 N / 1.455 m²

P = 0.368 Pa