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26 July, 23:54

What potential difference is needed to stop an electron that has an initial velocity v=6.0

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  1. 27 July, 00:21
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    Formula for kinetic energy of an object:

    KE = 0.5mv²

    m is the mass and v is the velocity.

    Formula for the work done on a charged object by moving it through a potential difference:

    W = ΔVq

    ΔV is the potential difference and q is the charge of the object.

    To find the potential difference needed to decelerate an electron to rest, set the work done on the electron equal to its kinetic energy:

    W = KE

    Substitute W = ΔVq and KE = 0.5mv²

    ΔVq = 0.5mv²

    Given values:

    q = 1.6*10⁻¹⁹C

    m = 9.11*10⁻³¹kg

    v = 6.0m/s

    Plug in the given values and solve for ΔV

    ΔV*1.6*10⁻¹⁹ = 0.5*9.11*10⁻³¹*6.0²

    ΔV = 1.02*10⁻¹⁰V
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