A jet aircraft is traveling at 291 m / s in horizontal flight. The engine takes in air at a rate of 63.8 kg/s and burns fuel at a rate of 1.21 kg/s. The exhaust gases are ejected at 667 m/s relative to the aircraft. Find the thrust of the jet engine and the delivered power.

thrust = 24795.87 N

Power = 7.215 MW

Explanation:

given data

The speed of the jet v = 291 m/s

The air intake is dMa/dt = 63.8 kg/s

The fuel burn rate is dMf/dt = 1.21 kg/s

The speed of the exhaust gas is u = 667 m/s

to find out

thrust of the jet engine and the delivered power

solution

first we get here rate of mass change in the rocket that is

rate of mass change dM/dt = 63.8 + 1.21

rate of mass change dM/dt = 65.01 kg/s

and

The thrust on the rocket will be here

thrust T = (dM/dt) u - (dMa/dt) v ... 1

thrust T = (65.01) 667 - (63.8) 291

thrust T = 24795.87 N

and

now the power of the rocket will be here

Power = speed * thrust ... 2

Power = 291 * 24795.87

Power = 7.215 MW