Two objects are dropped from different heights at the same instant. If the first object takes 10.7 seconds to hit the ground and the second takes 14.8 seconds what was the difference in their original heights?

The answer to your question is : 521.8 m

Explanation:

dа ta:

Different heights

Time first object (tfo) = 10.7 s

Time second object (tso) = 14.8 s

Initial speed of both objects (vo) = 0 m/s

a = 9.81 m/s²

Formula:

h = vot + 1/2 (a) (t) ² but vo = 0 so, h = 1/2 (a) (t) ²

Then, height fo h = 1/2 (9.81) (10.7) ² = 561.6 m

height so h = 1/2 (9,81) (14.8) ² = 1074.4 m

Difference in their heights = 1074.4 m - 561.6 m = 521.8 m