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4 October, 17:34

A projectile is launched at an angle of 30° from the horizontal and lands 69 s later at the same height from which it was launched. (a) What is the initial speed of the projectile (in m/s) ?

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  1. 4 October, 17:48
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    679.2 m/s

    Explanation:

    The formula for the time of flight of a projectile is given as,

    T = 2usinФ/g ... Equation 1

    Where T = Time of flight, u = initial velocity, Ф = angle of projectile to the horizontal, g = acceleration due to gravity.

    make u the subject of the equation

    u = Tg/2sinФ ... Equation 2

    Given: T = 69 s, Ф = 30°

    Constant: g = 9.8 m/s²

    Substitute into equation 2

    u = (69*9.8) / (2*sin30)

    u = 679.2 m/s.

    Hence the initial speed of the projectile is 679.2 m/s
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