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26 July, 11:25

An elementary particle of mass m completely absorbs a photon, after which its mass is 1.01m. (a) what was the energy of the incoming photon? (b) why is that energy greater than 0.01mc2?

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  1. 26 July, 11:42
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    A.) We use the famous equation proposed by Albert Einstein written below:

    E = Δmc²

    where

    E is the energy of the photon

    Δm is the mass defect, or the difference of the mass before and after the reaction

    c is the speed of light equal to 3*10⁸ m/s

    Substituting the value:

    E = (1.01m - m) * (3*10⁸ m/s) = 0.01mc² = 3*10⁶ Joules

    b) The actual energy may be even greater than 3*10⁶ Joules because some of the energy may have been dissipated. Not all of the energy will be absorbed by the photon. Some energy would be dissipated to the surroundings.
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