You are using a rope to lift a 14.5 kg crate of fruit. Initially you are lifting the crate at 0.500 m/s. You then increase the tension in the rope to 150 N and lift the crate an additional 1.15 m. During this d motion, how much work is done on the crate by the tension force?

W = 172.5 J

Explanation:

given,

mass of the fruit crate = 14.5 kg

initial velocity to lift = 0.500 m/s

increase in the tension = 150 N

lift of crate = 1.15 m

work done by the tension = ?

work done = force x displacement

W = F s cos θ

θ = 0°

W = F s x cos 0

W = 150 x 1.15 x 1

W = 172.5 J

Work done on the crate by the tension force = W = 172.5 J