An electromagnetic wave is traveling through free space. The amplitudes of the wave's electric and magnetic fields are E 0 E0 and B 0 B0, respectively. The wave then passes through a filter that reduces the amplitude of the electric field by half (E 0 / 2) (E0/2). What is the amplitude of the magnetic field after the wave passes through the filter?

B = Bo/2

Explanation:

Bo depends on Eo as stated by the relation

Bo = Eo/c

Where

Bo = magnetic field amplitude

Eo = Electric field amplitude

c = Speed of light in vacuum = constant

Since c is constant whatever happens to the electric field amplitude will also affect the magnetic field amplitude. In the same vein if the electric field amplitude is halfed, the magnetic field amplitude will also be halfed. Hence

(Bo) new = Bo/2

B = Bo / 2

Explanation:

Magnesium and electric fields are related in an electromagnetic wave

E / B = c

If the electric field is halved the magnetic field must also be halved to meet the written equation

B = Bo / 2