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27 August, 06:58

You set out to reproduce Thomson's e/m experiment with an accelerating potential of 150 V and adeflecting electric field of magnitude 6.0 * 106 N/C (a) At what fraction of the speed of light do the electrons move? (b) What magnetic-field magnitude will yield zero beam deflection? (c) With this magnetic field, how will the electron beam behave if you increase the acceleratingpotential above 150 V?

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  1. 27 August, 07:15
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    a. v' = 24.22 x 10 ⁻³

    b. β = 0.825 T

    Explanation:

    V = 150 V, E = 6.0 x 10 ⁶ N / C

    a.

    ¹/₂ * m * v² = e * V

    v = √ 2 * e / m * V

    v = √ 2 * 1.76 x 10 ¹¹ * 150 v = √ 5.28 x 10 ¹³

    v = 7.26 x 10 ⁶ m / s

    v' / c = 7.26 x 10 ⁶ m / s / 3.0 x 10 ⁸ = 24.22 x 10 ⁻³

    b.

    β = E / V

    β = 6.0 x 10 ⁶ / 7.266 x 10 ⁶

    β = 0.825 T

    c.

    When the increasing the accelerating potential speed it doesn't change the up wired the electric force and the magnetic force the electron be beat down more.
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