How does the capacitance of two identical capacitors connected in series compare to that of one of the capacitors?

Question

Milton

Physics

26 January, 04:48

How does the capacitance of two identical capacitors connected in series compare to that of one of the capacitors?

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Answers (1)

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Aubrey Carrillo · Answer 1

Don't add, whatever you do. This is how it should be done.

1/c = 1/c1 + 1/c1

1/c = (c1 + c1) / (c1*c1)

1/c = 2c1/c1^2 = 2/c1

c = c1/2 divide the value of one of the original capacitors by 2.

It means that whatever the value of one of the 2 capacitors is, you get the result of the two capacitors by dividing the value of one of them by 2.

It is similar to the result of putting 2 equal resistors in parallel.