Ask Question
9 June, 11:20

5-111. A box having a weight of 8 lb is moving around in a circle of radius rA = 2 ft with a speed of (vA) 1 = 5 ft>s while connected to the end of a rope. If the rope is pulled inward with a constant speed of vr = 4 ft>s, determine the speed of the box at the instant rB = 1 ft. How much work is done after pulling in the rope from A to B? Neglect friction and the size of the box.

+3
Answers (1)
  1. 9 June, 11:48
    0
    a) vB = 10.77 ft/s

    b) W = 11.30 lb*ft

    Explanation:

    a) W = 8 lb ⇒ m = W/g = 8 lb/32.2 ft/s² = 0.2484 slug

    vA lin = 5 ft/s

    rA = 2 ft

    v rad = 4 ft/s

    vB = ?

    rB = 1 ft

    W = ?

    We can apply The law of conservation of angular momentum

    Lin = Lfin

    m*vA*rA = m*vB*rB ⇒ vB = vA*rA / rB

    ⇒ vB = (5 ft/s) * (2 ft) / (1 ft) = 10 ft/s (tangential speed)

    then we get

    vB = √ (vB tang² + vB rad²) ⇒ vB = √ ((10 ft/s) ² + (4 ft/s) ²)

    ⇒ vB = 10.77 ft/s

    b) W = ΔK = KB - KA = 0.5*m*vB² - 0.5*m*vA²

    ⇒ W = 0.5*m * (vB² - vA²) = 0.5*0.2484 slug * ((10.77 ft/s) ² - (5 ft/s) ²)

    ⇒ W = 11.30 lb*ft
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “5-111. A box having a weight of 8 lb is moving around in a circle of radius rA = 2 ft with a speed of (vA) 1 = 5 ft>s while connected to ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers