A student uses a spring to launch a marble vertically in the air. the mass of the marble is 0.002kg and when the spring is stretched 0.05m it exerts a force of 20N. what is the maximum height the marble can reach?

Question

Lowery

Physics

10 October, 14:07

A student uses a spring to launch a marble vertically in the air. the mass of the marble is 0.002kg and when the spring is stretched 0.05m it exerts a force of 20N. what is the maximum height the marble can reach?

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Answers (1)

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Jaquan Ortiz · Answer 1

From the equestion:

F=mh:g

20N=0.002*0.05:10

let make pair subject:

hm=Fg

0.05m*0.002=20N*10

0.05m*0.002=200

0.05m=200-0.002=199.98 approximately 200.

0.05m:0.05m=200:0.05

m=4000

therefore; Maximum height is 4000m.