A ball whose mass is 0.3 kg hits the floor with a speed of 7 m/s and rebounds upward with a speed of 4 m/s. if the ball was in contact with the floor for 1.5 ms (1.5multiply10-3 s), what was the average magnitude of the force exerted on the ball by the floor? favg = 602.94 incorrect: your answer is incorrect. n.

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Lady

Physics

8 February, 23:19

A ball whose mass is 0.3 kg hits the floor with a speed of 7 m/s and rebounds upward with a speed of 4 m/s. if the ball was in contact with the floor for 1.5 ms (1.5multiply10-3 s), what was the average magnitude of the force exerted on the ball by the floor? favg = 602.94 incorrect: your answer is incorrect. n.

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Azaria Ritter · Answer 1

Newton's second law is stated as:

F=ma,

a = (7-4) / 1.5 = 2 m/s^2 (it is a deceleration due to impact with floor. And thus the ball exerts force on the floor).

Therefore,

F = 0.3*2 = 0.6 N