A cyclist rode the 1st 20 mile portion of his workout, at a constant speed. For the 12 mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the cyclist speed during the first portion, and find his speed during the cool down portion

Question

Marie Kidd

Engineering

29 May, 11:33

A cyclist rode the 1st 20 mile portion of his workout, at a constant speed. For the 12 mile cool down portion of his workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the cyclist speed during the first portion, and find his speed during the cool down portion

+2

Answers (1)

Know the Answer?

Salt · Answer 1

10 mph

Explanation:

20 / x = 12 / (x - 4)

Cross multiply

12x = 20 (x - 4)

12x = 20x - 80

80 = 20x - 12x

80 = 8x

divide through by '8'

10 = x

x = 10 mph