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26 June, 06:36

Doreen schmidt is a chemist. She needs to prepare 36 ounces of a 10% shydrochloric acid solution. Find the amount of 18% solution and the amount of 9% solution she should mix to get this solution

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  1. 26 June, 07:04
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    Total = 36oz

    Amount of 18% solution = x

    Amount of 9% solution = 36 - x

    Using the fact that (amount of solution) * (percent HCl) = amount HCl we can set up an expression for the amount HCl in a mixture of 18% and 9% solutions with a total volume of 36oz.

    Amount of HCl = x*0.18 + (36 - x) * 0.09

    If we divide this by the amount of solution we get percent HCl, and we have a target of 10% HCl. Now we have an equation to solve,

    [x*0.18 + (36 - x) * 0.09]/36 = 0.1

    x*0.09 + 3.24 = 3.6

    .09x = 0.36

    x = 4

    Therefore,

    4 ounces of 18% HCl solution and 32 ounces of 9% HCl solution

    Check:

    [ (4*.18) + (.09*32) ]/36 = 0.1?

    0.1 = 0.1 Yes.
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