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14 December, 21:38

Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

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  1. 14 December, 21:58
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    The weight of the load is (mass) x (gravity).

    The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance)

    The power is (work) / (time) =

    (mass) x (gravity) x (distance) / (time) =

    (500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =

    (500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =

    (500 x 9.8 x 12 / 1) newton - meter / sec =

    (500 x 9.8 x 12 / 1) joule / sec =

    58,800 watts

    = 58.8 kW

    = about 78.8 horsepower
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